Understanding the Problem
Let’s assume that the original distance covered is D units and the original time taken is T hours. The original speed would be D/T units per hour. According to the problem, twice the original distance, which is 2D units, is covered in four times the original time, which is 4T hours.
Solving the Problem Mathematically
If the speed remains constant, we can use the formula Speed = Distance/Time. So, the speed for the first case would be D/T and for the second case would be 2D/4T, which simplifies to D/2T.
Calculating the Ratio of the Two Speeds
The ratio of the two speeds is the speed of the second case divided by the speed of the first case. Therefore, (D/2T) / (D/T) = D/2T * T/D = 1/2.
Conclusion
The ratio of the two speeds is 1:2. This means that the speed at which twice the distance is covered in four times the time is half of the speed at which the original distance was covered in the original time.
